(A) The spin-only magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu = 2.

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(A) The spin-only magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.For $\mu = 2.84 \ BM$,we have $\sqrt{n(n+2)} = 2.84$,which implies $n(n+2) \approx 8$,so $n = 2$.In a $d^2$ configuration (weak ligand field),there are $2$ unpaired electrons.Thus,$n = 2$ and $\mu = \sqrt{2(2+2)} = \sqrt{8} = 2.84 \ BM$.

Class 12 Chemistry Coordination Compounds Isomerism and Magnetic properties

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For which of the following configurations is the spin-only magnetic moment value $2.84 \ BM$?

A
$d^2$ (in weak ligand field)
B
$d^4$ (in strong ligand field)
C
$d^4$ (in weak ligand field)
D
$d^5$ (in strong ligand field)

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For which of the following configurations is the spin-only magnetic moment value $2.84 \ BM$?

Similar Questions

Which of the following complexes is optically inactive?

What is the spin-only magnetic moment (in Bohr Magneton units) of $Ni^{2+}$ in an aqueous solution? (Atomic number of $Ni = 28$)

The spin-only magnetic moment value of the square planar complex $[Pt(NH_3)_2 Cl(NH_2 CH_3)] Cl$ is $B.M.$ (Nearest integer). (Given atomic number for $Pt = 78$)

In the coordination compound $[Co(en)_2Cl_2]Cl$,which of the following statements is false?

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