If the line passing through the points (-5, 1 | vedclass

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(B) Let the first line be $L_1$ passing through $A(-5, 1, 3)$ and $B(1, 2, 0)$. The direction ratios of $L_1$ are $(1 - (-5), 2 - 1, 0 - 3) = (6, 1, -

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$-7/2$

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(B) Let the first line be $L_1$ passing through $A(-5, 1, 3)$ and $B(1, 2, 0)$. The direction ratios of $L_1$ are $(1 - (-5), 2 - 1, 0 - 3) = (6, 1, -3)$.Let the second line be $L_2$ passing through $C(x, 2, 1)$ and $D(0, -4, 6)$. The direction ratios of $L_2$ are $(0 - x, -4 - 2, 6 - 1) = (-x, -6, 5)$.Since the lines $L_1$ and $L_2$ are perpendicular,the dot product of their direction ratios must be zero:$(6)(-x) + (1)(-6) + (-3)(5) = 0$$-6x - 6 - 15 = 0$$-6x - 21 = 0$$-6x = 21$$x = -21/6 = -7/2$.

If the line passing through the points $(-5, 1, 3)$ and $(1, 2, 0)$ is perpendicular to the line passing through the points $(x, 2, 1)$ and $(0, -4, 6)$,then $x = \dots$

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