The equation of the axis of the parabola x^2 | vedclass

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Question

(C) Given the equation of the parabola: $x^2 - 4x - 3y + 10 = 0$ Rearranging the terms to complete the square for $x$: $x^2 - 4x = 3y - 10$ Adding $4$

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$x - 2 = 0$

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(C) Given the equation of the parabola: $x^2 - 4x - 3y + 10 = 0$ Rearranging the terms to complete the square for $x$: $x^2 - 4x = 3y - 10$ Adding $4$ to both sides: $x^2 - 4x + 4 = 3y - 10 + 4$ $(x - 2)^2 = 3y - 6$ $(x - 2)^2 = 3(y - 2)$ This is in the form $(x - h)^2 = 4a(y - k)$,where the axis of the parabola is given by $x - h = 0$. Comparing,we get $h = 2$. Therefore,the equation of the axis is $x - 2 = 0$.

The equation of the axis of the parabola $x^2 - 4x - 3y + 10 = 0$ is:

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