A point P(5, -1) divides the line segment joi | vedclass

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(C) Let the coordinates of point $B$ be $(x, y)$.Given that point $P(5, -1)$ divides the segment $AB$ in the ratio $m:n = 2:3$.Using the section formu

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$(-4, 2)$

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(C) Let the coordinates of point $B$ be $(x, y)$.Given that point $P(5, -1)$ divides the segment $AB$ in the ratio $m:n = 2:3$.Using the section formula,the coordinates of $P$ are given by:$P = \left( \frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n} \right)$Substituting the values:$5 = \frac{2(x) + 3(11)}{2+3} \implies 5 = \frac{2x + 33}{5} \implies 25 = 2x + 33 \implies 2x = -8 \implies x = -4$$-1 = \frac{2(y) + 3(-3)}{2+3} \implies -1 = \frac{2y - 9}{5} \implies -5 = 2y - 9 \implies 2y = 4 \implies y = 2$Therefore,the coordinates of point $B$ are $(-4, 2)$.

$A$ point $P(5, -1)$ divides the line segment joining points $A(11, -3)$ and $B(x, y)$ in the ratio $2:3$. Find the coordinates of point $B$.

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