If the side length of a cube is 7.203 m,then | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The volume of a cube is given by $V = a^3$,where $a$ is the side length.Given $a = 7.203 \ m$.$V = (7.203)^3 = 373.714754627 \ m^3$.According to t

Vedclass · Accepted Answer

$373.7$

Vedclass · Answer

(C) The volume of a cube is given by $V = a^3$,where $a$ is the side length.Given $a = 7.203 \ m$.$V = (7.203)^3 = 373.714754627 \ m^3$.According to the rules of significant figures,the result of a multiplication or power should have the same number of significant figures as the measurement with the fewest significant figures.The value $7.203$ has $4$ significant figures.Therefore,the result should be rounded to $4$ significant figures.Rounding $373.714754627$ to $4$ significant figures gives $373.7 \ m^3$.

If the side length of a cube is $7.203 \ m$,then its volume is ............ $m^3$.

Similar Questions

An object of mass $m = 3.513 \ kg$ moves along the $x$-axis with a velocity of $5.00 \ ms^{-1}$. The magnitude of its momentum can be recorded as $...... \ kg \ ms^{-1}$.

If $97.52$ is divided by $2.54$,the correct result in terms of significant figures is

Three measurements are made as $18.425 \, cm$,$7.21 \, cm$,and $5.0 \, cm$. The addition should be written as ........ $cm$.

The number of significant figures in $23.023$,$0.0003$,and $2.1 \times 10^{-3}$ are respectively:

An object of mass $4.237 \, g$ occupies a volume of $1.72 \, cm^3$. The density of the object to appropriate significant figures is ......... $g \, cm^{-3}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module