Two cars of equal mass m moving with the same | vedclass

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(A) Let the two cars have mass $m$ and velocity $v$. They collide at an angle $	heta$ between their paths.By the principle of conservation of linear

Vedclass · Accepted Answer

$v \cos \frac{	heta}{2}$

Vedclass · Answer

(A) Let the two cars have mass $m$ and velocity $v$. They collide at an angle $	heta$ between their paths.By the principle of conservation of linear momentum,the component of momentum along the direction of the combined motion must be conserved.The initial momentum of each car along the direction of the resultant motion is $mv \cos(	heta/2)$.Since there are two cars,the total initial momentum is $P_i = mv \cos(	heta/2) + mv \cos(	heta/2) = 2mv \cos(	heta/2)$.After the collision,the two cars stick together and move with a common velocity $V$. The total mass is $2m$.The final momentum is $P_f = (2m)V$.Equating initial and final momentum: $2mV = 2mv \cos(	heta/2)$.Therefore,the final velocity is $V = v \cos(	heta/2)$.

Two cars of equal mass $m$ moving with the same speed $v$ undergo a perfectly inelastic collision. What is the velocity of the combined mass after the collision?

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