A wire of length 2 m and cross-sectional are | vedclass

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(A) When a wire is fixed at both ends (or prevented from expanding),the thermal stress developed due to a change in temperature $\Delta 	heta$ is giv

Vedclass · Accepted Answer

$1.32 	imes 10^7 \ N/m^2$

Vedclass · Answer

(A) When a wire is fixed at both ends (or prevented from expanding),the thermal stress developed due to a change in temperature $\Delta 	heta$ is given by the formula: $\sigma = Y \alpha \Delta 	heta$.Here,$Y = 1.2 	imes 10^{11} \ N/m^2$,$\alpha = 1.1 	imes 10^{-5} \ ^oC^{-1}$,and $\Delta 	heta = 10^oC$.Substituting the values:$\sigma = (1.2 	imes 10^{11}) 	imes (1.1 	imes 10^{-5}) 	imes 10$$\sigma = 1.32 	imes 10^{11} 	imes 10^{-4}$$\sigma = 1.32 	imes 10^7 \ N/m^2$.Note: The applied force of $200 \ N$ is irrelevant to the calculation of thermal stress in this context as the question asks for the stress due to temperature change.

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