If J is the angular momentum of a planet revo | vedclass

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(B) The areal velocity of a radius vector is given by $\frac{dA}{dt} = \frac{1}{2} r^2 \frac{d	heta}{dt} = \frac{1}{2} r^2 \omega$.The angular moment

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$\frac{J}{2m}$

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(B) The areal velocity of a radius vector is given by $\frac{dA}{dt} = \frac{1}{2} r^2 \frac{d	heta}{dt} = \frac{1}{2} r^2 \omega$.The angular momentum of the planet is $J = I \omega = mr^2 \omega$,where $m$ is the mass of the planet,$r$ is the distance from the Sun,and $\omega$ is the angular velocity.From this,we can express $r^2 \omega$ as $\frac{J}{m}$.Substituting this into the areal velocity formula: $\frac{dA}{dt} = \frac{1}{2} \left( \frac{J}{m} ight) = \frac{J}{2m}$.

If $J$ is the angular momentum of a planet revolving around the Sun,what is the areal velocity of the planet?

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