Two liquids of densities rho_1 = 1 and rho_2 | vedclass

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(B) Let the mass of each liquid be $m$. The total mass of the mixture is $M = m + m = 2m$.The volume of the first liquid is $V_1 = m / \rho_1$ and the

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$4/3$

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(B) Let the mass of each liquid be $m$. The total mass of the mixture is $M = m + m = 2m$.The volume of the first liquid is $V_1 = m / ho_1$ and the volume of the second liquid is $V_2 = m / ho_2$.The total volume of the mixture is $V = V_1 + V_2 = m / ho_1 + m / ho_2 = m(\frac{ho_1 + ho_2}{ho_1 ho_2})$.The density of the mixture is $ho = \frac{M}{V} = \frac{2m}{m(\frac{ho_1 + ho_2}{ho_1 ho_2})} = \frac{2ho_1 ho_2}{ho_1 + ho_2}$.Substituting the given values $ho_1 = 1$ and $ho_2 = 2$:$ho = \frac{2 	imes 1 	imes 2}{1 + 2} = \frac{4}{3}$.

Two liquids of densities $\rho_1 = 1$ and $\rho_2 = 2$ are mixed in equal masses. What is the density of the resulting mixture?

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