If a substance of mass m_1 and specific gravi | vedclass

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(C) Specific gravity $s = \frac{	ext{Density of mixture}}{	ext{Density of water}}$.Density of mixture $ho_{mix} = \frac{	ext{Total mass}}{	ext{T

Vedclass · Accepted Answer

$\frac{m_1 + m_2}{\left( \frac{m_1}{s_1} + \frac{m_2}{s_2} \right)}$

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(C) Specific gravity $s = \frac{	ext{Density of mixture}}{	ext{Density of water}}$.Density of mixture $ho_{mix} = \frac{	ext{Total mass}}{	ext{Total volume}} = \frac{m_1 + m_2}{V_1 + V_2}$.Since $V = \frac{m}{ho}$ and $ho = s \cdot ho_w$,we have $V_1 = \frac{m_1}{s_1 ho_w}$ and $V_2 = \frac{m_2}{s_2 ho_w}$.Substituting these into the density formula: $ho_{mix} = \frac{m_1 + m_2}{\frac{m_1}{s_1 ho_w} + \frac{m_2}{s_2 ho_w}} = \frac{m_1 + m_2}{\frac{1}{ho_w} \left( \frac{m_1}{s_1} + \frac{m_2}{s_2} ight)}$.Therefore,the specific gravity $s_{mix} = \frac{ho_{mix}}{ho_w} = \frac{m_1 + m_2}{\frac{m_1}{s_1} + \frac{m_2}{s_2}}$.

If a substance of mass $m_1$ and specific gravity $s_1$ is mixed with a substance of mass $m_2$ and specific gravity $s_2$,what is the specific gravity of the mixture?

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