Two capillary tubes of the same radius but lengths $l_1$ and $l_2$ are connected in parallel at the bottom of a vessel. What should be the length of a single capillary tube of the same radius that replaces both,such that the flow rate remains the same?

  • A
    $l_1 + l_2$
  • B
    $\frac{1}{l_1} + \frac{1}{l_2}$
  • C
    $\frac{l_1 l_2}{l_1 + l_2}$
  • D
    $\frac{1}{l_1 + l_2}$

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