(D) The mass of the particle is $m = 10 \, g = 10 \times 10^{-3} \, kg = 0.01 \, kg$.The amplitude is $A = 0.5 \, m$.The angular frequency is $\omega

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(D) The mass of the particle is $m = 10 \, g = 10 \times 10^{-3} \, kg = 0.01 \, kg$.The amplitude is $A = 0.5 \, m$.The angular frequency is $\omega = 10 \, rad/s$.The maximum force $F_{max}$ in simple harmonic motion is given by the formula $F_{max} = m \omega^2 A$.Substituting the values: $F_{max} = 0.01 \times (10)^2 \times 0.5$.$F_{max} = 0.01 \times 100 \times 0.5$.$F_{max} = 1 \times 0.5 = 0.5 \, N$.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

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$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?

A
$25$
B
$5$
C
$2.5$
D
$0.5$

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Acceleration and Force of Simple Harmonic Motion

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$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?

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