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(D) The electric potential $V$ at a distance $r$ from a point charge $Q$ is given by $V = \frac{1}{4\pi\varepsilon_0}\frac{Q}{r}$.Point $A$ is at a di

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(D) The electric potential $V$ at a distance $r$ from a point charge $Q$ is given by $V = \frac{1}{4\pi\varepsilon_0}\frac{Q}{r}$.Point $A$ is at a distance $l$ from point $B$ (where charge $+Q$ is located),so the potential at $A$ is $V_A = \frac{1}{4\pi\varepsilon_0}\frac{Q}{l}$.Point $C$ is also at a distance $l$ from point $B$,so the potential at $C$ is $V_C = \frac{1}{4\pi\varepsilon_0}\frac{Q}{l}$.Since $V_A = V_C$,the potential difference between points $A$ and $C$ is $\Delta V = V_C - V_A = 0$.The work done $W$ in moving a charge $q'$ between two points is given by $W = q' \Delta V$.Therefore,the work done in moving charge $(-q)$ from $A$ to $C$ is $W = (-q) 	imes 0 = 0$.

How much work is required to move a charge $(-q)$ from point $A$ to point $C$ in the presence of a charge $+Q$ at point $B$ as shown in the figure?

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