How much work is required to increase the vol | vedclass

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(D) The work done to change the potential energy of a capacitor is equal to the change in its stored energy.Initial energy $U_i = \frac{1}{2} C V_1^2

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$9 	imes 10^{-4}\ J$

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(D) The work done to change the potential energy of a capacitor is equal to the change in its stored energy.Initial energy $U_i = \frac{1}{2} C V_1^2 = \frac{1}{2} 	imes (6 	imes 10^{-6}\ F) 	imes (10\ V)^2 = 3 	imes 10^{-4}\ J$.Final energy $U_f = \frac{1}{2} C V_2^2 = \frac{1}{2} 	imes (6 	imes 10^{-6}\ F) 	imes (20\ V)^2 = 12 	imes 10^{-4}\ J$.Work done $W = \Delta U = U_f - U_i = (12 - 3) 	imes 10^{-4}\ J = 9 	imes 10^{-4}\ J$.

How much work is required to increase the voltage of a $6\,\mu F$ capacitor from $10\ V$ to $20\ V$?

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