An ammeter with a resistance of $0.018 \, \Omega$ can measure $1 \, A$. What shunt resistance is required to enable it to measure $10 \, A$?

$A$ galvanometer whose resistance is $120 \, \Omega$ gives full-scale deflection with a current of $0.05 \, A$. To enable it to read a maximum current of $10 \, A$,a shunt resistance is added in parallel with it. The resistance of the ammeter so formed is .............. $\Omega$.

The resistance of a galvanometer coil is $R$. What is the shunt resistance required to convert it into an ammeter of range $4$ times?

If the current is doubled,the deflection is also doubled in

An ammeter with a resistance of $2 \,\Omega$ can measure up to $100 \,mA$. What resistance (in $\Omega$) must be connected in series to make it measure up to $5 \,V$?

When a resistance of $100 \Omega$ is connected in series with a galvanometer of resistance $R$,its range is $V$. To double its range,a resistance of $1000 \Omega$ is connected in series. Find $R$. (in $\Omega$)