$A$ substance has a mass of $1 \, g$ and a density of $5 \, g/cm^3$. Its magnetic dipole moment is $6 \times 10^{-7} \, A \cdot m^2$. What is the magnetization in $A/m$?

The relation between total magnetic field $(B)$,magnetic intensity $(H)$,permeability of free space $(\mu_{0})$,and magnetic susceptibility $(\chi)$ is:

The domain in a ferromagnetic material is in the form of a cube of side $2 \mu m$. The number of atoms in that domain is $9 \times 10^{10}$ and each atom has a dipole moment of $9 \times 10^{-24} A m^2$. The magnetization of the domain is (approximately):

The percentage increase in magnetic field $(B)$ when the space within a current-carrying solenoid is filled with magnesium (magnetic susceptibility $\chi_{mg} = 1.2 \times 10^{-5}$) is:

The magnetic susceptibility of a material of a rod is $499$. Permeability in vacuum is $4\pi \times 10^{-7} \text{ H/m}$. Absolute permeability of the material of the rod is $....\pi \times 10^{-4} \text{ H/m}$.

$A$ domain in ferromagnetic iron is in the form of a cube of side length $1\; \mu m$. Estimate the number of iron atoms in the domain and the maximum possible dipole moment and magnetisation of the domain. The molecular mass of iron is $55\; g/mol$ and its density is $7.9\; g/cm^3$. Assume that each iron atom has a dipole moment of $9.27 \times 10^{-24}\; A m^2$.