For a common emitter transistor,the current g | vedclass

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(D) Given:Current gain $(\beta)$ = $50$Input resistance $(R_i)$ = $1 \ k\Omega = 1000 \ \Omega$Input voltage $(V_i)$ = $0.01 \ V$First,calculate the b

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$500 \ \mu A$

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(D) Given:Current gain $(\beta)$ = $50$Input resistance $(R_i)$ = $1 \ k\Omega = 1000 \ \Omega$Input voltage $(V_i)$ = $0.01 \ V$First,calculate the base current $(i_b)$ using Ohm's law:$i_b = \frac{V_i}{R_i} = \frac{0.01 \ V}{1000 \ \Omega} = 10^{-5} \ A$Now,calculate the collector current $(i_c)$ using the current gain formula:$i_c = \beta 	imes i_b$$i_c = 50 	imes 10^{-5} \ A$$i_c = 5 	imes 10^{-4} \ A = 500 	imes 10^{-6} \ A = 500 \ \mu A$

For a common emitter transistor,the current gain is $50$,the input resistance is $1 \ k\Omega$,and the input voltage is $0.01 \ V$. What is the collector current?

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