Ray 1 is parallel to the horizontal mirror. R | vedclass

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(B) Let the angle between the two mirrors be $	heta$.From the geometry of the reflection,the angle of incidence equals the angle of reflection.Given

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(B) Let the angle between the two mirrors be $	heta$.From the geometry of the reflection,the angle of incidence equals the angle of reflection.Given that the incident ray is parallel to the horizontal mirror and the reflected ray is parallel to the inclined mirror,we can form a triangle with the two mirrors.The interior angles of this triangle are $	heta, 	heta,$ and $	heta$ based on the properties of parallel lines and reflection angles.Since the sum of the interior angles of a triangle is $180^o$,we have:$	heta + 	heta + 	heta = 180^o$$3	heta = 180^o$$	heta = 60^o$

Ray $1$ is parallel to the horizontal mirror. Ray $2$ is parallel to the other mirror. Then the angle between the two mirrors is .......... $^o$.

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