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Question

(A) When a plane mirror rotates with an angular velocity $\omega$,the reflected ray rotates with an angular velocity of $2\omega$.Given the frequency

Vedclass · Accepted Answer

$4\pi nR$

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(A) When a plane mirror rotates with an angular velocity $\omega$,the reflected ray rotates with an angular velocity of $2\omega$.Given the frequency of rotation of the mirror is $n$ revolutions per second,the angular velocity of the mirror is $\omega_m = 2\pi n 	ext{ rad/s}$.The angular velocity of the reflected ray is $\omega_r = 2 	imes \omega_m = 2 	imes (2\pi n) = 4\pi n 	ext{ rad/s}$.The speed $v$ of the light spot on the spherical screen of radius $R$ is given by $v = \omega_r 	imes R$.Substituting the values,we get $v = (4\pi n) 	imes R = 4\pi nR$.

$A$ small plane mirror is placed at the center of a spherical screen of radius $R$. Light rays are incident on the mirror. If the mirror is rotated at a frequency of $n$ revolutions per second,what will be the speed of the reflected light spot on the screen?

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