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(A) When primary $(1^o)$ alcohols are passed over red-hot copper at $573 \ K$ $(300 \ ^oC)$,they undergo dehydrogenation to form aldehydes.$R-CH_2OH \

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Aldehyde and ketone respectively

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(A) When primary $(1^o)$ alcohols are passed over red-hot copper at $573 \ K$ $(300 \ ^oC)$,they undergo dehydrogenation to form aldehydes.$R-CH_2OH \xrightarrow{Cu/573 \ K} R-CHO + H_2$When secondary $(2^o)$ alcohols are passed over red-hot copper at $573 \ K$,they undergo dehydrogenation to form ketones.$R_2CHOH \xrightarrow{Cu/573 \ K} R_2C=O + H_2$Thus,primary and secondary alcohols yield aldehydes and ketones respectively.

What is obtained by the reaction of primary and secondary alcohols with red-hot copper?

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