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(C) $1-propanol$ $(CH_3CH_2CH_2OH)$ on heating with $Cu$ at $573 \ K$ undergoes dehydrogenation to form propanal $(CH_3CH_2CHO)$,which is an aldehyde.

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Oxidation by heating with copper followed by reaction with Fehling's solution

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(C) $1-propanol$ $(CH_3CH_2CH_2OH)$ on heating with $Cu$ at $573 \ K$ undergoes dehydrogenation to form propanal $(CH_3CH_2CHO)$,which is an aldehyde. Aldehydes give a positive test with Fehling's solution. $2-propanol$ $(CH_3CH(OH)CH_3)$ on heating with $Cu$ at $573 \ K$ undergoes dehydrogenation to form propanone $(CH_3COCH_3)$,which is a ketone. Ketones do not give a positive test with Fehling's solution. Other reagents like $KMnO_4$ or acidic dichromate oxidize $1-propanol$ to propanoic acid,which does not react with Fehling's solution,and concentrated $H_2SO_4$ causes dehydration to propene.

Which of the following processes is best suited to distinguish between $1-propanol$ and $2-propanol$?

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