Ethyl ester xrightarrow{CH_3MgBr} P. What wil | vedclass

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(A) The reaction of an ester with a Grignard reagent $(R'MgX)$ proceeds in two steps to form a tertiary alcohol. First,the ester reacts with one equiv

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$(CH_3)_3COH$

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(A) The reaction of an ester with a Grignard reagent $(R'MgX)$ proceeds in two steps to form a tertiary alcohol. First,the ester reacts with one equivalent of the Grignard reagent to form a ketone intermediate. $RCOOR'' + R'MgX \rightarrow RCOR' + R''OMgX$. Then,the ketone reacts with a second equivalent of the Grignard reagent to form the tertiary alcohol after acidic hydrolysis. $RCOR' + R'MgX$ $\rightarrow R(R')_2COMgX$ $\xrightarrow{H_3O^+} R(R')_2COH$. For ethyl acetate $(CH_3COOC_2H_5)$ reacting with methylmagnesium bromide $(CH_3MgBr)$: $1$. $CH_3COOC_2H_5 + CH_3MgBr \rightarrow CH_3COCH_3 + C_2H_5OMgBr$ (Acetone is formed). $2$. $CH_3COCH_3 + CH_3MgBr \rightarrow (CH_3)_3COMgBr$. $3$. $(CH_3)_3COMgBr + H_2O/H^+ \rightarrow (CH_3)_3COH + Mg(OH)Br$. The final product is tert-butyl alcohol,$(CH_3)_3COH$.

Ethyl ester $\xrightarrow{CH_3MgBr} P$. What will be the product $P$?

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