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(B) The reaction of phenol with $CHCl_3$ (chloroform) and aqueous $NaOH$ (sodium hydroxide) is known as the Reimer-Tiemann reaction.In this reaction,a

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Salicylaldehyde

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(B) The reaction of phenol with $CHCl_3$ (chloroform) and aqueous $NaOH$ (sodium hydroxide) is known as the Reimer-Tiemann reaction.In this reaction,a formyl group $(-CHO)$ is introduced at the ortho position of the phenol ring.The product formed is $2$-hydroxybenzaldehyde,commonly known as Salicylaldehyde.The reaction is represented as:$C_6H_5OH + CHCl_3 + 3NaOH \rightarrow C_6H_4(OH)(CHO) + 3NaCl + 2H_2O$

Which of the following products is obtained when phenol is treated with $CHCl_3$ and $NaOH$?

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