What is the product obtained from the oxymercuration of $1-butyne$ using $HgSO_4$ and $H_2SO_4$?
- A$CH_3CH_2COCH_3$
- B$CH_3CH_2CH_2CHO$
- C$CH_3CH_2CHO + HCHO$
- D$CH_3CH_2COOH + HCHO$
Explore More
Similar Questions
In the reaction,$CH_3-C \equiv C-CH_3 \xrightarrow{(i) X, (ii) Zn/H_2O} CH_3-C(=O)-C(=O)-CH_3$,$X$ is:
Medium
View SolutionThe reagent which could distinguish between $1-$hexyne and $1-$hexene is
Medium
View Solution$2-$butyne is reduced to $trans-but-2-ene$ using:
Which is the most suitable reagent among the following to distinguish compound $(3)$ from the rest of the compounds?
$1. CH_3-C \equiv C-CH_3$
$2. CH_3-CH_2-CH_2-CH_3$
$3. CH_3-CH_2-C \equiv CH$
$4. CH_3-CH=CH_2$
$1. CH_3-C \equiv C-CH_3$
$2. CH_3-CH_2-CH_2-CH_3$
$3. CH_3-CH_2-C \equiv CH$
$4. CH_3-CH=CH_2$
MediumAIIMS 2015
View SolutionIn the following reaction:
$C_2H_2$ $\xrightarrow[HgSO_4 / H_2SO_4]{H_2O} (x)$ $\xrightarrow{\text{Tautomerisation}} CH_3-CHO$
$(x)$ is $:-$
$C_2H_2$ $\xrightarrow[HgSO_4 / H_2SO_4]{H_2O} (x)$ $\xrightarrow{\text{Tautomerisation}} CH_3-CHO$
$(x)$ is $:-$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo