When mesityl oxide undergoes the iodoform rea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Mesityl oxide is $(CH_3)_2C=CH-CO-CH_3$. It contains a methyl ketone group $(-COCH_3)$,which undergoes the iodoform reaction with $I_2$ and $NaOH$

Vedclass · Accepted Answer

$(CH_3)_2C=CH-COOH$

Vedclass · Answer

(C) Mesityl oxide is $(CH_3)_2C=CH-CO-CH_3$. It contains a methyl ketone group $(-COCH_3)$,which undergoes the iodoform reaction with $I_2$ and $NaOH$. The reaction is: $(CH_3)_2C=CH-CO-CH_3 + 3I_2 + 4NaOH \rightarrow (CH_3)_2C=CH-COONa + CHI_3 + 3NaI + 3H_2O$. The organic acid salt formed is sodium salt of $3-$methylbut$-2-$enoic acid. Therefore,the corresponding acid is $(CH_3)_2C=CH-COOH$.

When mesityl oxide undergoes the iodoform reaction,one of the products obtained is a sodium salt of an organic acid. Which acid is formed?

Similar Questions

Which of the following reactions cannot be used to convert $R_2CO$ to $R_2CH_2$?

The product of the following reaction is :

Identify the reagent used in the transformation of a ketone into a semicarbazone.

$Ph-C(=O)-CH_3 \xrightarrow{NaOCl} A + \text{salt}$
$A + CH_3-C(=O)-CH_3 \rightarrow B$
$B$ is

Identify the name of the reaction in which the carbonyl group of aldehydes and ketones is reduced to a methylene group upon treatment with hydrazine,followed by heating with sodium hydroxide in ethylene glycol.

Vedclass Test Series

Exam Paper Generator

Online Exam Module