Consider the acidity of the following carboxy | vedclass

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(B) The presence of an electron-withdrawing group $(-NO_2)$ on the benzene ring increases the acidity of benzoic acid.$1$. The ortho-substituted isome

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$II > III > IV > I$

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(B) The presence of an electron-withdrawing group $(-NO_2)$ on the benzene ring increases the acidity of benzoic acid.$1$. The ortho-substituted isomer $(II)$ is the most acidic due to the ortho-effect.$2$. The para-isomer $(III)$ has a strong $-I$ and $-M$ effect,making it more acidic than the meta-isomer.$3$. The meta-isomer $(IV)$ only exerts a $-I$ effect,making it more acidic than benzoic acid $(I)$ but less acidic than the para-isomer.$4$. Benzoic acid $(I)$ has no electron-withdrawing substituent.Therefore,the correct order of acidity is $II > III > IV > I$.

Consider the acidity of the following carboxylic acids:
$(I)$ $PhCOOH$
$(II)$ $o-NO_2C_6H_4COOH$
$(III)$ $p-NO_2C_6H_4COOH$
$(IV)$ $m-NO_2C_6H_4COOH$
Which of the following is the correct order of acidity?

Similar Questions

Which of the following is most acidic?

Rearrange the following in the increasing order of acidic strength:
$(i)$ benzoic acid $(ii)$ $p$-methoxybenzoic acid $(iii)$ $o$-methoxybenzoic acid

In the reaction,the product $D$ is:
$CH_2=CH_2$ $\xrightarrow{Br_2/CCl_4} A$ $\xrightarrow{KCN} B$ $\xrightarrow{H_3O^{+}} C$ $\xrightarrow{\Delta} D$

Which of the following is most reactive for decarboxylation?

Consider the acidity of the following carboxylic acids. Which of the following orders is correct?
$A$. $PhCOOH$
$B$. $o-NO_2C_6H_4COOH$
$C$. $p-NO_2C_6H_4COOH$
$D$. $m-NO_2C_6H_4COOH$

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Consider the acidity of the following carboxylic acids:$(I)$ $PhCOOH$$(II)$ $o-NO_2C_6H_4COOH$$(III)$ $p-NO_2C_6H_4COOH$$(IV)$ $m-NO_2C_6H_4COOH$Which of the following is the correct order of acidity?