IUPAC name for the compound | vedclass

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(C) $1$. Identify the longest carbon chain containing the double bond. The chain has $5$ carbons,so the parent alkane is $pentane$,and the alkene is $

Vedclass · Accepted Answer

trans $2$-chloro,$3$-iodo,$pent-2$-ene

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(C) $1$. Identify the longest carbon chain containing the double bond. The chain has $5$ carbons,so the parent alkane is $pentane$,and the alkene is $pent-2$-ene.$2$. Number the chain to give the double bond the lowest possible locant. Numbering from left to right gives the double bond at position $2$.$3$. Substituents are $chloro$ at position $2$ and $iodo$ at position $3$.$4$. Determine the configuration: The high-priority groups ($Cl$ on $C-2$ and $CH_2CH_3$ on $C-3$) are on opposite sides of the double bond,which corresponds to the $trans$ configuration.$5$. Combining these,the name is $trans-2-chloro-3-iodopent-2-ene$.

$IUPAC$ name for the compound

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