CH_2=CH_2 xrightarrow{Br_2/H_2O} A. In the ab | vedclass

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(A) The reaction of ethene $(CH_2=CH_2)$ with bromine water $(Br_2/H_2O)$ is an electrophilic addition reaction. In the presence of water,the bromoniu

Vedclass · Accepted Answer

Ethylene bromohydrin

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(A) The reaction of ethene $(CH_2=CH_2)$ with bromine water $(Br_2/H_2O)$ is an electrophilic addition reaction. In the presence of water,the bromonium ion intermediate is attacked by the water molecule (nucleophile) instead of the bromide ion. The reaction is: $CH_2=CH_2 + Br_2 + H_2O \rightarrow CH_2(Br)-CH_2(OH) + HBr$. The product $CH_2(Br)-CH_2(OH)$ is known as ethylene bromohydrin (or $2-$bromoethanol). Therefore,the correct option is $A$.

$CH_2=CH_2 \xrightarrow{Br_2/H_2O} A$. In the above reaction,the compound $A$ is:

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