If sets $A$ and $B$ are defined as follows:
$A = \{ (x, y) : y = e^x, x \in R \}$
$B = \{ (x, y) : y = x, x \in R \}$
Then:
$A = \{ (x, y) : y = e^x, x \in R \}$
$B = \{ (x, y) : y = x, x \in R \}$
Then:
- A$B \subseteq A$
- B$A \subseteq B$
- C$A \cap B = \phi$
- D$A \cup B = A$
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