$A$ cylinder is rolling down an inclined plane of inclination $30^\circ$ without slipping. Its linear acceleration along the inclined plane will be:

$A$ solid cylinder is rolling down on an inclined plane of angle $\theta$. The coefficient of static friction between the plane and the cylinder is $\mu_s$. The condition for the cylinder not to slip is

Which of the following is true about the angular momentum of a cylinder rolling down a slope without slipping?

If a sphere is rolling,the ratio of its rotational energy to the total kinetic energy is given by

$A$ solid sphere of radius $R$ undergoes pure rolling down a plane inclined to the horizontal at an angle $\theta$. If the radius of gyration is $k$, then its acceleration is

Two identical uniform discs roll without slipping on two different surfaces $AB$ and $CD$ (see figure) starting at $A$ and $C$ with linear speeds $v_1$ and $v_2$,respectively,and always remain in contact with the surfaces. If they reach $B$ and $D$ with the same linear speed and $v_1 = 3 \ m/s$,then $v_2$ in $m/s$ is $(g = 10 \ m/s^2)$.