Class 11PhysicsSystem of Particles and Rotational MotionConservation of angular momentum (combined translation and rotational motion)
Difficult$A$ thin circular ring of mass $M$ and radius $r$ is rotating with a constant angular velocity $\omega$. Two particles,each of mass $m$,are attached to the opposite ends of a diameter of the ring. The new angular velocity of the ring will be:
- A$\frac{\omega (M - 2m)}{M + 2m}$
- B$\frac{\omega M}{M + 2m}$
- C$\frac{\omega M}{M + m}$
- D$\frac{\omega (M + 2m)}{M}$
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