$AlF_3$ is soluble in $HF$ only in the presence of $KF$. This is due to the formation of:

  • A
    $K_3[AlF_3H_3]$
  • B
    $K_3[AlF_6]$
  • C
    $AlH_3$
  • D
    $K[AlF_3H]$

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