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(D) According to Raoult's Law,the total pressure $P_T$ of an ideal binary solution is given by the sum of the partial pressures of the components:$P_T

Vedclass · Accepted Answer

$p_B + x_A(p_A - p_B)$

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(D) According to Raoult's Law,the total pressure $P_T$ of an ideal binary solution is given by the sum of the partial pressures of the components:$P_T = P_A + P_B$We know that $P_A = p_A x_A$ and $P_B = p_B x_B$,where $p_A$ and $p_B$ are the vapour pressures of pure components.Substituting these into the equation:$P_T = p_A x_A + p_B x_B$Since $x_A + x_B = 1$,we have $x_B = 1 - x_A$.Substituting $x_B$ in the equation:$P_T = p_A x_A + p_B(1 - x_A)$$P_T = p_A x_A + p_B - p_B x_A$$P_T = p_B + x_A(p_A - p_B)$

$p_A$ and $p_B$ are the vapour pressure of pure liquid components,$A$ and $B,$ respectively of an ideal binary solution. If $x_A$ represents the mole fraction of component $A,$ the total pressure of the solution will be

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