D(+)-glucose reacts with hydroxylamine (NH_2O | vedclass

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Question

(D) $D(+)$-glucose contains an aldehyde group at $C1$. When it reacts with hydroxylamine $(NH_2OH)$,the carbonyl oxygen is replaced by $=NOH$ to form

Vedclass · Accepted Answer

$CH=NOH - C(H)(OH) - C(OH)(H) - C(H)(OH) - C(H)(OH) - CH_2OH$

Vedclass · Answer

(D) $D(+)$-glucose contains an aldehyde group at $C1$. When it reacts with hydroxylamine $(NH_2OH)$,the carbonyl oxygen is replaced by $=NOH$ to form an oxime. The configuration of the chiral centers ($C2$ to $C5$) remains the same as in $D$-glucose ($C2-OH$ right,$C3-OH$ left,$C4-OH$ right,$C5-OH$ right). The structure is: $CH=NOH - C(H)(OH) - C(OH)(H) - C(H)(OH) - C(H)(OH) - CH_2OH$.

$D(+)$-glucose reacts with hydroxylamine $(NH_2OH)$ and yields an oxime. The structure of the oxime would be:

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