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(C) When two mirrors are placed at an angle of $90^{\circ}$,they form three images of an object placed in front of them. Let the two mirrors be $M_1$

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The eye $1$ can see the image of eye $2$ only and eye $2$ can see the image of eye $1$ only.

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(C) When two mirrors are placed at an angle of $90^{\circ}$,they form three images of an object placed in front of them. Let the two mirrors be $M_1$ (along the $y$-axis) and $M_2$ (along the $x$-axis). Let the eyes be at positions $E_1$ and $E_2$. $1$. The image of $E_1$ formed by $M_1$ is $E_1'$ (reflected across $M_1$).$2$. The image of $E_2$ formed by $M_2$ is $E_2'$ (reflected across $M_2$).$3$. The image of $E_1$ formed by $M_2$ is $E_1''$ and the image of $E_2$ formed by $M_1$ is $E_2''$.Due to the geometry of the setup,the light rays from eye $E_1$ reflecting off mirror $M_2$ will appear to come from the image $E_1''$,which is located such that it is visible to eye $E_2$. Similarly,light rays from eye $E_2$ reflecting off mirror $M_1$ will appear to come from the image $E_2''$,which is visible to eye $E_1$. Thus,eye $1$ sees the image of eye $2$,and eye $2$ sees the image of eye $1$.

$A$ two-eyed man is looking at the junction of two mutually perpendicular mirrors from a far-off distance. Assume no reflection occurs from the edge. If both eyes are open,then:

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