A flexible chain of weight W hangs between tw | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Consider half of the chain. The vertical component of the tension at the support must balance half the weight of the chain.$T \sin 	heta = \frac{

Vedclass · Accepted Answer

$\frac{W}{2} \cot 	heta$

Vedclass · Answer

(C) Consider half of the chain. The vertical component of the tension at the support must balance half the weight of the chain.$T \sin 	heta = \frac{W}{2}$At the lowest point (mid-point),the tension is purely horizontal,let this be $T_0$.For the equilibrium of the half-chain,the horizontal component of the tension at the support must be equal to the tension at the lowest point.$T \cos 	heta = T_0$From the first equation,$T = \frac{W}{2 \sin 	heta}$.Substituting this into the second equation:$T_0 = \left( \frac{W}{2 \sin 	heta} ight) \cos 	heta$$T_0 = \frac{W}{2} \cot 	heta$

$A$ flexible chain of weight $W$ hangs between two fixed points $A$ and $B$ which are at the same horizontal level. The inclination of the chain with the horizontal at both the points of support is $\theta$. What is the tension of the chain at the mid-point?

Similar Questions

$A$ box of mass $m$ is in equilibrium under the application of three forces as shown below. If the magnitude of $F_1$ is $10 \ N$, what is the magnitude of $F_3$ (in $N$)?

At the instant $t = 0$,a force $F = kt$ ($k$ is a constant) acts on a small body of mass $m$ resting on a smooth horizontal surface. The force is applied at an angle $\alpha$ with the horizontal. The time at which the body leaves the surface is:

Two masses $m$ and $M$ are attached to the strings as shown in the figure. If the system is in equilibrium,then

When is a body said to be in mechanical equilibrium?

What will be the tension produced in the string $PQ$ for the given system?

Vedclass Test Series

Exam Paper Generator

Online Exam Module