A student is asked to measure the wavelength | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The fringe width $\beta$ of a double-slit interference pattern is given by the formula: $\beta = \frac{D \lambda}{d}$In this expression,$D$ is the

Vedclass · Accepted Answer

decrease the distance between $S_2$ and $S_3$

Vedclass · Answer

(B) The fringe width $\beta$ of a double-slit interference pattern is given by the formula: $\beta = \frac{D \lambda}{d}$In this expression,$D$ is the distance between the screen (or microscope) and the plane containing the slits,$\lambda$ is the wavelength of the light used,and $d$ is the distance between the two coherent sources (slits $S_2$ and $S_3$).In the given setup,the distance $d$ between $S_2$ and $S_3$ is $5 	ext{ cm}$,which is very large for a typical Young's double-slit experiment. Because $\beta$ is inversely proportional to $d$,a large value of $d$ results in extremely narrow fringes that are too close together to be resolved by the microscope $M$.To make the interference fringes visible,the fringe width $\beta$ must be increased. Since $\beta \propto \frac{1}{d}$,the student should decrease the distance $d$ between the slits $S_2$ and $S_3$.

Similar Questions

In Young's double-slit interference experiment,the ratio of the slit widths is $1:25$. Find the ratio of the maximum to minimum intensity in the interference pattern.

The figure shows a schematic diagram of the arrangement of Young's Double Slit Experiment. If the distance $d$ is varied,then identify the correct statement.

In a Young's double-slit experiment,the fringe width is $0.8 \, mm$ when light of wavelength $6000 \, \mathring{A}$ is used,and the screen is at a distance of $2.5 \, m$. If the experiment is performed in a liquid with a refractive index of $1.6$,the new fringe width will be.....$mm$.

White light is used to illuminate two slits in Young's double-slit experiment. The separation between the slits is $b$ and the screen is at a distance $d (d >> b)$ from the slits. The wavelengths missing at a point on the screen directly in front of one of the slits are

Vedclass Test Series

Exam Paper Generator

Online Exam Module