A source of power 4 kW emits 10^{20} photons | vedclass

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(B) Given: Power $P = 4 \ kW = 4000 \ W$,Number of photons $n = 10^{20}$,Time $t = 1 \ s$.The energy of one photon is given by $E = \frac{P \cdot t}{n

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$X$-rays

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(B) Given: Power $P = 4 \ kW = 4000 \ W$,Number of photons $n = 10^{20}$,Time $t = 1 \ s$.The energy of one photon is given by $E = \frac{P \cdot t}{n}$.$E = \frac{4000 	imes 1}{10^{20}} = 4 	imes 10^{-17} \ J$.To find the frequency $
u$,we use $E = h
u$,where $h = 6.63 	imes 10^{-34} \ J \cdot s$.$
u = \frac{E}{h} = \frac{4 	imes 10^{-17}}{6.63 	imes 10^{-34}} \approx 6.03 	imes 10^{16} \ Hz$.The frequency range for $X$-rays is typically $3 	imes 10^{16} \ Hz$ to $3 	imes 10^{19} \ Hz$.Since the calculated frequency falls within this range,the radiation lies in the $X$-ray region.

$A$ source of power $4 \ kW$ emits $10^{20}$ photons in $1 \ s$. In which region of the electromagnetic spectrum does the emitted radiation lie?

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