The Z vs P graph for four gases is given belo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The compressibility factor $Z$ is defined as $Z = \frac{PV}{nRT}$.For real gases,the deviation from ideal behavior is represented by the dip in th

Vedclass · Accepted Answer

$D$

Vedclass · Answer

(A) The compressibility factor $Z$ is defined as $Z = \frac{PV}{nRT}$.For real gases,the deviation from ideal behavior is represented by the dip in the $Z$ vs $P$ curve.$A$ greater dip indicates stronger intermolecular forces of attraction.Stronger intermolecular forces of attraction correspond to a higher critical temperature $(T_c)$,as it is easier to liquefy the gas.In the given graph,the curve for gas $D$ shows the maximum deviation (the deepest dip) from the ideal behavior $(Z=1)$.Therefore,gas $D$ has the strongest intermolecular forces and the highest critical temperature.

The $Z$ vs $P$ graph for four gases is given below at the same temperature.
Which of the gases will have the highest value of critical temperature $(T_c)$?

Similar Questions

When is deviation more in the behaviour of a gas from the ideal gas equation $PV = nRT$?

What is the Boyle temperature?

$A$ gas described by van der Waal's equation:

The pressure of a van der Waals gas is less than the pressure of an ideal gas because of

Calculate the compressibility factor for $SO_2$,if $1 \ mol$ of it occupies $0.35 \ L$ at $300 \ K$ and $50 \ atm$ pressure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The $Z$ vs $P$ graph for four gases is given below at the same temperature.Which of the gases will have the highest value of critical temperature $(T_c)$?