ACl_2 (excess) + BCl_2 rightarrow ACl_4 + B d | vedclass

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(B) The reaction $ACl_2 + BCl_2 \rightarrow ACl_4 + B \downarrow$ indicates that $A$ is oxidized from $+2$ to $+4$ and $B$ is reduced from $+2$ to $0$

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Cinnabar

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(B) The reaction $ACl_2 + BCl_2 \rightarrow ACl_4 + B \downarrow$ indicates that $A$ is oxidized from $+2$ to $+4$ and $B$ is reduced from $+2$ to $0$.This behavior is characteristic of $Sn$ $(A)$ and $Hg$ $(B)$,where $SnCl_2$ acts as a reducing agent.The thermal decomposition of $BO$ $(HgO)$ at temperatures $> 400 \ ^oC$ yields $Hg$ and $O_2$ $(HgO \rightarrow Hg + \frac{1}{2} O_2)$.Since $B$ is $Hg$,its common ore is $HgS$,which is known as Cinnabar.

$A$. Feldspar	$I$. $[Ag_3SbS_3]$
$B$. Asbestos	$II$. $Al_2O_3 \cdot H_2O$
$C$. Pyrargyrite	$III$. $MgSO_4 \cdot H_2O$
$D$. Diaspore	$IV$. $KAlSi_3O_8$
	$V$. $CaMg_3(SiO_3)_4$

Column-$I$ (Ores)	Column-$II$ (Metals)
$A$. Sylvine	Potassium
$B$. Malachite	Magnesium
$C$. Cinnabar	Mercury
$D$. Fluorite (Fluorspar)	Calcium

$ACl_2$ (excess) + $BCl_2$ $\rightarrow$ $ACl_4$ + $B \downarrow$
$BO \xrightarrow[\Delta]{> 400 \ ^oC} \frac{1}{2} O_2 + B$
If $A$ and $B$ are metals,then the ore of $B$ would be:

Similar Questions

Peacock ore is:

Match the following items in List-$I$ with their corresponding formulas in List-$II$.
$A$. Feldspar $I$. $[Ag_3SbS_3]$
$B$. Asbestos $II$. $Al_2O_3 \cdot H_2O$
$C$. Pyrargyrite $III$. $MgSO_4 \cdot H_2O$
$D$. Diaspore $IV$. $KAlSi_3O_8$
$V$. $CaMg_3(SiO_3)_4$

The chief impurity present in red bauxite is:

Find the incorrectly matched pair?
Column-$I$ (Ores) Column-$II$ (Metals)
$A$. Sylvine Potassium
$B$. Malachite Magnesium
$C$. Cinnabar Mercury
$D$. Fluorite (Fluorspar) Calcium

Which one of the following statements is correct?

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$ACl_2$ (excess) + $BCl_2$ $\rightarrow$ $ACl_4$ + $B \downarrow$ $BO \xrightarrow[\Delta]{> 400 \ ^oC} \frac{1}{2} O_2 + B$If $A$ and $B$ are metals,then the ore of $B$ would be: