P is obtained by reductive ozonolysis of whic | vedclass

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(B) The reaction between cyclohexanone and acrolein in the presence of a base $(	ext{OH}^-, \Delta)$ is a Robinson annulation reaction. $1$. The base

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Bicyclo[ $4.3$ . $0$ ]non-$1$ $(6)$-ene

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(B) The reaction between cyclohexanone and acrolein in the presence of a base $(	ext{OH}^-, \Delta)$ is a Robinson annulation reaction. $1$. The base abstracts an $\alpha$-hydrogen from cyclohexanone to form an enolate. $2$. This enolate undergoes a Michael addition with acrolein. $3$. Subsequent intramolecular aldol condensation followed by dehydration leads to the formation of a bicyclic enone. $4$. The product $P$ is a bicyclic enone with the molecular formula $C_{10}H_{14}O_2$. $5$. Reductive ozonolysis of a bicyclic alkene breaks the double bond to form a dicarbonyl compound. $6$. By analyzing the structure of the Robinson annulation product, it is identified as bicyclo[ $4.3$ . $0$ ]non-$1$ $(6)$-en-$3$-one. $7$. The precursor alkene that yields this structure upon ozonolysis is bicyclo[ $4.3$ . $0$ ]non-$1$ $(6)$-ene.

$P$ is obtained by reductive ozonolysis of which of the following compounds? The reaction is given as:
Cyclohexanone + Acrolein $\xrightarrow{\text{OH}^-, \Delta} P$ (dicarbonyl compound) $(mf = C_{10}H_{14}O_2)$

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$P$ is obtained by reductive ozonolysis of which of the following compounds? The reaction is given as: Cyclohexanone + Acrolein $\xrightarrow{\text{OH}^-, \Delta} P$ (dicarbonyl compound) $(mf = C_{10}H_{14}O_2)$