n-hexane xrightarrow{Al_2O_3/Delta} (A) xrigh | vedclass

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(A) $1$. $n$-hexane undergoes aromatization in the presence of $Al_2O_3/\Delta$ to form benzene $(A)$.$2$. Benzene $(A)$ reacts with $CO + HCl$ in the

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Compound $B$ forms a silver mirror on reaction with $[Ag(NH_3)_2]OH$.

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(A) $1$. $n$-hexane undergoes aromatization in the presence of $Al_2O_3/\Delta$ to form benzene $(A)$.$2$. Benzene $(A)$ reacts with $CO + HCl$ in the presence of $AlCl_3$ (Gattermann-Koch reaction) to form benzaldehyde $(B)$.$3$. Statement $A$: Benzaldehyde $(B)$ does not form a silver mirror with Tollen's reagent $([Ag(NH_3)_2]OH)$ because it is an aromatic aldehyde and does not reduce it under standard conditions.$4$. Statement $B$: The Gattermann-Koch reaction involves $CO$ and $HCl$ forming $HCOCl$ in situ,which reacts with $AlCl_3$ to form the formyl cation $(HCO^+)$. The reaction mechanism is bimolecular $(A + E^+)$,not trimolecular.$5$. Statement $C$: Benzene diazonium chloride reacts with $H_3PO_2$ and $H_2O$ to form benzene $(A)$. This is correct.$6$. Statement $D$: Benzaldehyde does not give a grey color with $HgCl_2$ (which is a test for formic acid or specific reducing agents).$7$. The question asks for the incorrect statement. Both $A$ and $B$ are technically incorrect,but in the context of standard chemistry problems,$A$ is the most commonly cited incorrect property.

$n$-hexane $\xrightarrow{Al_2O_3/\Delta} (A)$ $\xrightarrow{(CO + HCl)/AlCl_3} (B)$. Select the incorrect statement among the following:

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