The $K_{sp}$ for $AgBr$ at $25 \, ^\circ C$ is $4.9 \times 10^{-13}$. How much $AgBr$ (in grams) will dissolve in $20 \, L$ of its saturated solution? (Molecular weight of $AgBr = 188$)

  • A
    $7 \times 10^{-7} \times 188 \, g$
  • B
    $14 \times 10^{-6} \times 188 \, g$
  • C
    $14 \times 10^{-7} \times 188 \, g$
  • D
    $7 \times 10^{-7} \times (188)^{-1} \, g$

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