A and B are two concentric conducting spheric | vedclass

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(C) $1$. Let the charge on inner shell $A$ be $+Q$. Due to induction,a charge of $-Q$ is induced on the inner surface of shell $B$.$2$. Since shell $B

Vedclass · Accepted Answer

The electric field between $A$ and $B$ is non-zero.

Vedclass · Answer

(C) $1$. Let the charge on inner shell $A$ be $+Q$. Due to induction,a charge of $-Q$ is induced on the inner surface of shell $B$.$2$. Since shell $B$ is earthed,its potential is zero. The potential at $B$ is due to the charge on $A$ and the charge on $B$ itself. Let the charge on the outer surface of $B$ be $q'$. The potential at $B$ is $V_B = kQ/r_B + kq'/r_B = 0$,which implies $q' = -Q$. However,since the shell is earthed,the charge on the outer surface becomes zero,and the total charge on $B$ is $-Q$.$3$. Electric field inside $A$ $(r $4$. Electric field between $A$ and $B$ $(r_A $5$. Electric field outside $B$ $(r > r_B)$: Since the shell $B$ is earthed,the potential is zero,and the charge on the outer surface is zero. Thus,$E = 0$.$6$. Comparing with options: Option $C$ is correct as the electric field between $A$ and $B$ is non-zero.

$A$ and $B$ are two concentric conducting spherical shells. $A$ is given a positive charge $+Q$ while $B$ is earthed. Then:

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