The IUPAC name for the compound shown below i | vedclass

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Question

(C) $1$. Identify the longest carbon chain containing the double bond. The chain has $5$ carbons,so the parent alkane is pentene.$2$. Number the chain

Vedclass · Accepted Answer

$Z-2-$chloro$-3-$iodo$-2-$pentene

Vedclass · Answer

(C) $1$. Identify the longest carbon chain containing the double bond. The chain has $5$ carbons,so the parent alkane is pentene.$2$. Number the chain to give the double bond the lowest possible locant. Numbering from the left gives the double bond at position $2$ $(CH_3-C(Cl)=C(I)-CH_2CH_3)$.$3$. The substituents are chloro at position $2$ and iodo at position $3$. The name is $2-$chloro$-3-$iodo$-2-$pentene.$4$. Determine the $E/Z$ configuration using Cahn-Ingold-Prelog priority rules.- At $C-2$: $Cl$ (atomic number $17$) has higher priority than $CH_3$ (atomic number $6$).- At $C-3$: $I$ (atomic number $53$) has higher priority than $CH_2CH_3$ (atomic number $6$).- The high-priority groups ($Cl$ and $I$) are on the same side of the double bond,which corresponds to the $Z$ configuration.$5$. Therefore,the correct name is $Z-2-$chloro$-3-$iodo$-2-$pentene.

The $IUPAC$ name for the compound shown below is:

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