A xrightarrow{KOBr} CHBr_3Here A is: | vedclass

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Question

(A) The reaction $A \xrightarrow{KOBr} CHBr_3$ represents the haloform reaction (specifically the bromoform reaction). Compounds containing the $CH_3C

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Isopropyl alcohol

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(A) The reaction $A \xrightarrow{KOBr} CHBr_3$ represents the haloform reaction (specifically the bromoform reaction). Compounds containing the $CH_3CO-$ group or the $CH_3CH(OH)-$ group undergo the haloform reaction. Among the given options,Isopropyl alcohol $(CH_3CH(OH)CH_3)$ contains the $CH_3CH(OH)-$ group. When treated with $KOBr$ (which acts as a source of $Br_2$ and $KOH$),it undergoes oxidation to acetone followed by bromination to form bromoform $(CHBr_3)$.

$A \xrightarrow{KOBr} CHBr_3$
Here $A$ is:

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$A \xrightarrow{KOBr} CHBr_3$Here $A$ is: