I. FeCr_2O_4 + NaOH + text{air} rightarrow Na | vedclass

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(C) In the extraction of chromium from chromite ore $(FeCr_2O_4)$,the ore is fused with $NaOH$ in the presence of air to form sodium chromate $(Na_2Cr

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dissolving in $H_2O$

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(C) In the extraction of chromium from chromite ore $(FeCr_2O_4)$,the ore is fused with $NaOH$ in the presence of air to form sodium chromate $(Na_2CrO_4)$ and iron$(III)$ oxide $(Fe_2O_3)$.$Na_2CrO_4$ is a soluble salt,whereas $Fe_2O_3$ is an insoluble metal oxide.Therefore,the mixture can be separated by dissolving the mass in water $(H_2O)$,where $Na_2CrO_4$ dissolves and $Fe_2O_3$ remains as a residue.

$I$. $FeCr_2O_4 + NaOH + \text{air} \rightarrow Na_2CrO_4 + Fe_2O_3$
$II$. $Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7$
$Na_2CrO_4$ and $Fe_2O_3$ are separated by:

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$I$. $FeCr_2O_4 + NaOH + \text{air} \rightarrow Na_2CrO_4 + Fe_2O_3$$II$. $Na_2CrO_4 + H_2SO_4 \rightarrow Na_2Cr_2O_7$$Na_2CrO_4$ and $Fe_2O_3$ are separated by: