What is the product 'A' in the following reac | vedclass

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(B) The reaction involves the acid-catalyzed ring opening of an epoxide. $1$. The oxygen atom of the epoxide is protonated by $H_3O^{\oplus}$ to form

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(B) The reaction involves the acid-catalyzed ring opening of an epoxide. $1$. The oxygen atom of the epoxide is protonated by $H_3O^{\oplus}$ to form a better leaving group. $2$. The ring opens to form a more stable carbocation intermediate. In this specific structure,the epoxide ring is fused to a five-membered ring. $3$. The nucleophilic attack by water $(H_2O)$ occurs at the more substituted carbon of the epoxide,followed by deprotonation to yield the diol product. $4$. The structure corresponds to a cyclopentane ring with a $-CH_2OH$ group at the top position and a tertiary alcohol group ($-OH$ and $-CH_3$) at the adjacent carbon. Therefore,the correct product is represented by option $B$.

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. $ROH + SOCl_2$	$i$. $RBr + NaHSO_4 + H_2O$
$B$. $ROH + PCl_5$	$ii$. $3RX + H_3PO_3$
$C$. $3ROH + PX_3$	$iii$. $RCl + SO_2 + HCl$
$D$. $ROH + NaBr + H_2SO_4$	$iv$. $RCl + POCl_3 + HCl$

What is the product '$A$' in the following reaction?
(Image of an epoxide ring fused to a cyclopentane ring with an exocyclic double bond,reacting with $H_3O^{\oplus}$ to form $A$.)

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What is the product '$A$' in the following reaction?(Image of an epoxide ring fused to a cyclopentane ring with an exocyclic double bond,reacting with $H_3O^{\oplus}$ to form $A$.)