Consider the following reaction sequence:C_6H | vedclass

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(D) The reaction of styrene $(C_6H_5CH=CH_2)$ with $Br_2$ is an electrophilic addition reaction across the double bond.This results in the formation o

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Styrene dibromide,benzoic acid

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(D) The reaction of styrene $(C_6H_5CH=CH_2)$ with $Br_2$ is an electrophilic addition reaction across the double bond.This results in the formation of styrene dibromide $(C_6H_5CH(Br)CH_2Br)$,which is compound $A$.When styrene dibromide is treated with $KMnO_4$ (a strong oxidizing agent),the side chain is oxidized.Specifically,the alkyl group attached to the benzene ring is oxidized to a carboxylic acid group,resulting in the formation of benzoic acid $(C_6H_5COOH)$,which is compound $B$.Therefore,$A$ is styrene dibromide and $B$ is benzoic acid.

Consider the following reaction sequence:
$C_6H_5CH=CH_2$ $\xrightarrow{Br_2} A$ $\xrightarrow{KMnO_4} B$
Compound $A$ and $B$ respectively are:

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Consider the following reaction sequence:$C_6H_5CH=CH_2$ $\xrightarrow{Br_2} A$ $\xrightarrow{KMnO_4} B$Compound $A$ and $B$ respectively are: