(C) The reaction sequence is as follows: $1$. $X$ is $Toluene$ $(C_6H_5CH_3)$. $2$. $Toluene$ reacts with $Cl_2$ in the presence of light (free radica

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(C) The reaction sequence is as follows: $1$. $X$ is $Toluene$ $(C_6H_5CH_3)$. $2$. $Toluene$ reacts with $Cl_2$ in the presence of light (free radical chlorination) to form $Benzotrichloride$ $(C_6H_5CCl_3)$. $3$. $Benzotrichloride$ undergoes hydrolysis to form $Benzoic \ acid$ $(C_6H_5COOH)$. Therefore,$X$ is $Toluene$ and $Y$ is $Benzoic \ acid$.

Class 12 Chemistry 8-2.Carboxylic acids and Their derivative Preparation of Carboxylic Acids and Their Derivatives

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$X$ $\xrightarrow{Cl_2} \text{Benzotrichloride}$ $\xrightarrow{\text{Hydrolysis}} Y$
$X$ and $Y$ respectively are :

A
Benzene,Benzaldehyde
B
Toluene,Benzaldehyde
C
Toluene,Benzoic acid
D
Benzene,Benzoic acid

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8-2.Carboxylic acids and Their derivative

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Preparation of Carboxylic Acids and Their Derivatives

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$X$ $\xrightarrow{Cl_2} \text{Benzotrichloride}$ $\xrightarrow{\text{Hydrolysis}} Y$ $X$ and $Y$ respectively are :

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$X$ $\xrightarrow{Cl_2} \text{Benzotrichloride}$ $\xrightarrow{\text{Hydrolysis}} Y$
$X$ and $Y$ respectively are :